A nuclide of 64/29 cu absorbs a positron. witch is the resulting atom

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Chemistry

Janiah Martin

14 September, 11:41

A nuclide of 64/29 cu absorbs a positron. witch is the resulting atom

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Tommy Lowe · Answer 1

We are given a nuclide 64Cu29 which absorbs a positron. A positron is an alpha particle with a symbol of 4α2. So, the nuclear reaction is:

64Cu29 + 4α2 = = = > 68Er31

The resulting atom is an Erbium with an atomic number of 68.