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8 June, 00:15

Based on this equation: 2AL + 3CuCl2 - > 2AlCl3 + Cu ... how many grams of copper (II) chloride dihydrate would be required to react completely with 1.20g of aluminum metal?

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  1. 8 June, 03:34
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    2Al + 3CuCl2 ➡ 2AlCl3 + 3Cu. Moles of Al = 1.2/27 = 0.045 moles 2 moles of Al reacts with 3 moles of CuCl2. Therefore, 1 mole of CuCl2 reacts with = 2/3 x moles of Al = 2/3 x 0.045 = 0.03 moles.
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