What is the volume of a gas at 2.00 atm and 200.0 K if its original volume was 300.0 L at 0.250 atm and 400.0 K

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Chemistry

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7 January, 09:45

What is the volume of a gas at 2.00 atm and 200.0 K if its original volume was 300.0 L at 0.250 atm and 400.0 K

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Sharon · Answer 1

Given:

P1 = 2.00 atm

T1 = 200.0 K

V2 = 300.0 L

P2 = 0.250 atm

T2 = 400.0 K

Required:

V1

Solution:

P1V1/T1 = P2V2/T2

(2.00 atm) V1 / (200.0 K) = (300.0 L) (0.250 atm) / (400.0 K)

V1 = 18.75 L