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23 November, 22:27

Lithium has two isotopes.

Li-6 and Li-7.

Li-6 mass = 6.015121amu

Li-7 mass = 7.016003amu

Lithium Mass = 6.94049amu

What is percent abundance of Li-6?

I know that there is an equation:

6.9409 = (% Abundance Li-6 * Weight of Li-6) + (% Abundance Li-7 * Weight of Li-7)

I don't know how to use it.

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Answers (1)
  1. 24 November, 01:09
    0
    This is in the assumption that these are the only 2 isotopes. This means that:

    abundance of Li-6 = X

    abundance of Li-7 = 1-X

    Hence from your equations

    6.9409 = (X * 6.015121amu) + ((1-X) * 7.016003amu)

    Solve for X = 0.075 or 7.50%
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