NaHCO3 (s) + HC2H3O2 (aq) = NaC2H3O2 (aq) + H2O (I) + CO2 (g)

Using the above formula, if I used 0.100L of 0.83 M HC2H3O2 (aq) (0.83 mol per 1 L of solution), how much carbon dioxide would be produced?

Question

Chemistry

Tyler Berger

22 May, 05:20

NaHCO3 (s) + HC2H3O2 (aq) = NaC2H3O2 (aq) + H2O (I) + CO2 (g)

Using the above formula, if I used 0.100L of 0.83 M HC2H3O2 (aq) (0.83 mol per 1 L of solution), how much carbon dioxide would be produced?

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Answers (1)

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Maximillian Mejia · Answer 1

Moles=volume*concentration

=0.1*.83

=.083 Moles of HC2H3O2

Mole ratio between HC2H3O2 and CO2 is 1:1

This means. 083 Moles of CO2

Mass = Moles*Rfm of CO2

=.083 * (12+16+16)

=3.7grams

NaHCO3 (s) + HC2H3O2 (aq) = NaC2H3O2 (aq) + H2O (I) + CO2 (g)Using the above formula, if I used 0.100L of 0.83 M HC2H3O2 (aq) (0.83 mol per 1 L of solution), how much carbon dioxide would be produced?

NaHCO3 (s) + HC2H3O2 (aq) = NaC2H3O2 (aq) + H2O (I) + CO2 (g)

Using the above formula, if I used 0.100L of 0.83 M HC2H3O2 (aq) (0.83 mol per 1 L of solution), how much carbon dioxide would be produced?