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27 May, 22:43

What is the molarity of a solution that contains 135g of KI in 4.0 L of solution?

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  1. 28 May, 01:31
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    Molar mass KI = 166.0028 g/mol

    number of moles solute:

    n = mass solute / molar mass

    n = 135 / 166.0028

    n = 0.813 moles

    Therefore:

    M = moles solute / volume

    M = 0.813 / 4.0 = > 0.20325 M
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