The reaction for the combustion of benzene is: 2C6H6 + 15O2 → 12 CO2 + 6 H2O. How moles of O2 are required to produce 130 g CO2 in the presence of excess C6H6?

a. 2.36

b. 2.95

c. 3.69

d. 5.80

2 C ₆ H ₆ + 15 O ₂ → 12 CO ₂ + 6 H ₂ O

if mass of CO ₂ = 130g

since moles = mass : molar mass

then moles of CO₂ = 130 g : ((12 * 1) + (16 * 2))

= 2.9545 mol

Mole ratio of CO₂ : O₂ is 12 : 15

∴ if mole of CO₂ = 2.9545 mol

then moles of O₂ = (2.9545 : 12) * 15

= 3.6931 mol

∴ the answer is Option C