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3 December, 11:37

How many grams of CIF3 form when. 204 moles of F2 react with excess Cl2?

The answer must be sold with dimensional analysis.

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  1. 3 December, 12:27
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    The reaction equation:

    2Cl₂ + 3F₂ → 2ClF₃

    Moles of F₂ = 0.204

    Moles of ClF₃ = 2/3 x 0.204

    = 0.136 mole

    Mass = moles x Mr

    = 0.136 x (35.5 + 19 x 3)

    = 12.58 grams of ClF₃ will be formed.
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