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29 July, 14:23

How much heat was absorbed or lost by the surroundings? use 4.184 j/goc for the specific heat of the solution. put your answer in units of kj and make sure the sign is correct?

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  1. 29 July, 14:39
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    To solve the amount heat that was added or lost in the surrounding, use the formula:

    q = m cp dt

    where q is the heat

    m is the mass of the substance

    cp is the specific heat of the subtance

    dt is the change in temperature (t2 - t1)

    just substitute the given value
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