Ammonia (NH3) reacts with sulfuric acid to form ammonium sulfate. How many grams of ammonium sulfate are obtained from 8.73 g of ammonia, assuming a 73% yield of product?

I hope you understand my working:

1) Finding the mol of NH3 to find the mol of (NH4) 2SO4 (ammonium sulfate)

2) Mr of (NH4) 2SO4

3) Theoretical yield: The actual grams of (NH4) 2SO4 produced when reacting 0.514 mol of NH3 to 0.514 mol H2SO4

4) Using formula of (given grams) / (theoretical grams or actual grams) * 100 = 73%

5) Basic algebra