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28 October, 18:12

How many moles of Fe2o3 are in 161 g of the compound?

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  1. 28 October, 19:18
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    M = 161g

    M = 56 * 2 + 16 * 3 = 160g/mol

    n = m/M = 161g / 160g/mol = 1,00625 mol
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