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2 February, 15:45

If you have 0.261 m3 of water at 25.0°C and add 0.127 m3 of water at 95.0°C, what is the final temperature of the mixture? Use 1000 kg/m3 as the density of water at any temperature.

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  1. 2 February, 19:01
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    Assuming that the specific heat capacity for both, we can rewrite the equation:

    q = m * Cp * (T2 - T1) to q = m * (T2 - T1)

    Equating them to each other we have:

    m1 * (T2 - T1) = m2 * (T2 - T3)

    0.261 * (T2 - 25) = 0.127 * (T2 - 95)

    T2 = - 41.34 degrees Celsius
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