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23 February, 20:21

If 250.0 ml of a 0.96 m solution of acetic acid (c2h4o2 are diluted to 800.0 ml, what will be the approximate molarity of the final solution?

a. 0.19 m strike reset

b. 0.24 m strike reset

c. 0.30 m strike reset

d. 0.77 m strike reset

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Answers (1)
  1. 23 February, 21:51
    0
    The answer is c. 0.30 m strike reset.

    Calculate the concentration of the solution after the dilution.

    C1 * V1 = C2 * V2

    The initial solution:

    C1 = 250 mL

    V1 = 0.96 M

    The final solution:

    C2 = ?

    V2 = 800 mL

    250 mL * 0.96 M = C2 * 800 mL

    C2 = 250 mL * 0.96 M / 800 mL

    C2 = 0.30 M
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