What is the molarity of hno3 (nitric acid if 20.0 ml of the solution is needed to exactly neutralize 10.0 ml of a 1.67 m naoh solution?

a. 3.34 m strike reset

b. 1.67 m strike reset

c. 0.835 m strike reset

d. 0.334 m strike reset?

In a neutralization reaction between an acid and the base, the molarity or volume of each can be determined using the equation: M_acid*V_acid = M_base*V_base. The unknown is the M_acid. Using the given values, the equation is M_hno3 = (10*1.67) / 20. The result is that the molarity of HNO3 to exactly neutralize the base is 0.835 M.