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30 May, 03:21

When 1.187 g of a metallic oxide is reduced with excess hydrogen 1.054 g of the metal is produced. what is the metallic oxide?

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  1. 30 May, 04:03
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    Mass O = 1.187 - 1.054 = 0.133 g

    Moles O = 0.133 g / 16 g/mol = 0.00831

    Moles metal = 2 x 0.00831 = 0.0166

    Atomic mass metal = 1.054 g / 0.0166 = 63.4 g/mol

    (this is the atomic mass of Cu)

    so the metal oxide is Cu2O
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