If 8.42 * 10-2 moles of aluminum react with 1.77 * 10-2 moles of chlorine gas, how many moles of AlCl3 may form?

The balanced equation that describes the reaction between aluminum and chlorine gas to produce aluminum chloride is expressed 2Al + 3Cl2 = 2AlCl3. We first determine the limiting reactant through the given number of moles. Considering the stoichiometric coefficient as well, the limiting reactant is chlorine. Hence, the number of moles of aluminum formed is 1.77x10^-2 * (2/3) or 0.0118 moles AlCl3.