Isotonic saline solution has a mass % nacl concentration of 0.900 %. assuming its density is 1.00 g/ml, what is its molarity

a. 9.00 x 10-3 m

b. 0.0900 m

c. 0.154 m

d. 0.900 m

e. 1.80 m

In this item, we calculate the moles of NaCl with the basis of 1L of solution.

First, calculate the mass of the solution using the density.

m = (1L) x (1000g/1000mL) (1000mL/1L) = 1000g

Then, we calculate mass of NaCl by multiplying the calculate value with the percentage.

m of NaCl = (1000 g) (0.0090) = 9 g

Then, calculate the moles of NaCl by the molar mass.

molarity = (9g) (1 mole / 58.44 g) = 0.1539 mole / L solution or 0.1529M. Then, the answer to this item is letter C.