Determine the oxidation number of the element that is underlined within the compound. Li2 SiO3

+2

+4

-2

-4

Determine the oxidation number of the element that is underlined within the compound.

Li2SiO3

Si = + 4

You forgot to underline the element.

I can give you the oxidation number for the three elements

Li: + 1 (this is the only oxidation number for this element)

O: - 2 (this is the only oxidation number when it is not forming a peroxide)

Then: Oxidation number of Si is calculated from X + 2 (+1) + 3 (-2) = 0

x + 2 - 6 = 0

x = 6 - 2

x = 4

The oxidation number of Si is + 4.