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8 May, 14:22

A 20.0 mL sample of a NaCl solution has a mass of 21.040 g. After the solution is evaporated to dryness, the dry salt residue has a mass of 4.348 g. Calculate the following concentrations for the NaCl solution.

a) Mass/mass%

b) Mass/volume%

c) Molarity (M)

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Answers (1)
  1. 8 May, 17:56
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    Mass NaCl = 4.348

    Mass solution = 21.040 - 4.348 = 16.692

    mass/mass % =

    4.348/16.692

    = 26%

    mass/vol % =

    21.7%

    Molecular mass of NaCl = 58.5

    Moles of NaCl = 0.074

    Volume of solution = 0.02 L

    Molarity = 3.7 mol/Liter
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