Complete and balance the following equation:

BrO3 - (aq) + N2H4 (aq) →Br2 (l) + N2 (g) (acidic solution)

Express your answer as a net chemical equation including phases.

You need to add the last substance to the products side (the right sode of the arrow). You have hydrogen and oxygen - water.

You get: BrO3 + N2H4 - > Br2 + N2 + H2O

# of Br: 1x1 = 1 # of Br: 2x1 = 2

O: 3x1 = 3 O: 1x1 = 1

N: 2x1 = 2 B N: 2x1 = 2

H: 4x1 = 4. H: 2x1 = 2

Br:

Multiply the reactant (left) side by 2 to balance.

O:

You've just multiplied the reactant oxygen by 2 so now the reactant side equals 6. Multiply the product (right) side by six as well.

H:

The product side is now equal to 12. Multiply the reactant side by 3 to balance.

N:

Now you have to balance N because the reactant side has been risen. So multiply the product side by three as well.

You end up with the complete and balanced equation:

2BrO3 + 3N2H4 - > Br2 + 3N2 + 6H2O