A gas with a volume of 4.00L at a pressure of 205 kPa is allowed to expand to a volume of 12.0L. What is the pressure of the container if the temperature remains constant?

Use the equation P1/V1=P2/V2.

Known values:

P1: 205 kPa

V1: 4.00 L

V2: 12.0 L

Unknown:

P2: let's call this variable x

205/4.00=x/12.0 (cross multiply)

205*12.0=x*4.00

2460=4.00x (divide each side by 4.00)

x = 615

P2: 615 kPa