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27 August, 21:20

Calculate the number of grams of oxygen required to convert 23.0 g of glucose to CO2 and H2O.

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Answers (2)
  1. 27 August, 23:47
    0
    Mr of C6H12O6 = (12*6) + (12*1) + (16*6) = 180

    Mr of O2 = (16*2) = 32

    If 180 g of glucose requires 6*32 g of oxygen

    38 g of glucose would need 6*32/180 * 38=40.53 g of oxygen

    ans=40.53

    mr of CO2=44

    If 180 g of glucose gives 44*6 g of CO2

    therefore 38 g of it gives 44*6/180 * 38 = 55.73 g of CO2
  2. 28 August, 00:54
    0
    I think that it equal to co=3 h=2 o=1
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