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9 August, 13:55

2NaN3=2Na+3N2. If 0.21 moles of NaN3 reacts, what mass of nitrogen would result

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  1. 9 August, 15:58
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    Use the mole ratio: 2 moles of NaN3 : 3 moles of N2

    you have : 0.21 moles of NaN3 : x moles N2

    Cross multiply: you get 0.3 moles for N2

    To find the mass = # of moles * molecular mass

    0.3 * 28

    = 8.4g
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