Calculate the molar solubility of PbCO3 when the Ksp of PbCO3 is 1.5*10^-15 at 25°C.

Question

Chemistry

Mahoney

14 July, 16:38

Calculate the molar solubility of PbCO3 when the Ksp of PbCO3 is 1.5*10^-15 at 25°C.

+4

Answers (1)

Know the Answer?

Mohamed Morales · Answer 1

First, write the dissociation equation for PbCO3 which is PbCO3 = Pb^ (2+) + CO3^ (2-). Then, write the Ksp equation which is Ksp = [Pb^ (2+) ][CO3^ (2-) ]. The equation suggests that there is 1:1 molar ratio between the Pb^ (2+), CO3^ (2-) and the dissolved PbCO3. Thus in equation form, we can represent them as x. The Ksp equation is then: 1.5*10^-15 = x^2. The molar solubility of PbCO3, x, is then equal to 3.87*10^-8 moles per liter.