Ask Question
16 September, 12:27

How would the vapor pressure of a solution that contains 0.5 mol of CaCl2 in 1.0 kg of water compare with the vapor pressure of a solution that contains 1.5 mol of glucose in 1.0 kg of water?

a) one-third as large

b) the same

c) three times as large

d) nine times as large

+4
Answers (1)
  1. 16 September, 12:56
    0
    Option b) the same

    Given that Ca Cl2 is a strong electrolyte it will dissolve completely and each mol will produce 3 times the number of mols.

    This means that 0.5 mol of CaCl2 will be equivalent to 1.5 mol of ions and then the change of the vapor pressure is the same than that of 1.5 mol / kg glucose.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “How would the vapor pressure of a solution that contains 0.5 mol of CaCl2 in 1.0 kg of water compare with the vapor pressure of a solution ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers