This calculation shows that burning ___ grams of methane (takes in/gives off) ___ energy

Formula for heat change: Q = mCΔTwhere

Q = the heat addedm = massC = specific heatΔT = (Tf - To in absolute temperature)

note: in this case subtracting the final and initial temperature in Kelvin or Celsius will not make a difference)

We add everything into the formula: ΔT = T (final) - T (original)

ΔT = 36.65 - 24.85ΔT = 11.8° CSo the change in temperature is 11.8 degrees

Q = 41.11x 4.319 x 11.8

Q = 2095.13 heat of combustion of Methane.

It shows that burning 41.11g of methane gives of 2095.13 Joules of energy

The question lacks some details in order to be answered. Nevertheless, let's just give some examples.

Given that you are to burn 10 kg of methane (CH4) from 0 to 20°C. The specific heat capacity of methane is 4.475 kJ/kg-K.

H = mCpT

H = (10kg) (4.475 kJ/kg-K) (20-0)

H = 895.00 kJ

Because of the positive value of enthalpy, methane takes in heat.