Ask Question
5 August, 07:21

A mixture of helium and neon gases has a density of 0.1562 g/L at 40.2°C and 296 torr. What is the mole fraction of neon in this mixture?

+5
Answers (1)
  1. 5 August, 07:59
    0
    You are given the density of helium and neon gas mixture which is 0.1562 grams per liters at 40.2degC and 296 torr. You are required to find the mole fraction of neon in this mmixture.

    c = dRT/P

    c = (0.1562g/L) (0.08206 L-atm/mol-K) (40.2+273) K/296torr (1atm/760torr)

    c = 10.31 g/mol

    since helium is 4 g/mol

    mole fraction of neon = (10.31 - 4) / 10.31 = 0.612
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A mixture of helium and neon gases has a density of 0.1562 g/L at 40.2°C and 296 torr. What is the mole fraction of neon in this mixture? ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers