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13 April, 02:43

1 mole of phosphoric acid (H3PO4) and 1.75 moles of NaOH are added to the one liter water. Calculate the pH.

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  1. 13 April, 03:09
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    Moles of H⁺ released by each mole of acid = 3

    Moles of H⁺ released = 3

    Moles of OH⁻ released = 1.75

    Moles of H⁺ remaining = 3 - 1.75 = 1.25 mol/dm³

    pH = - log[H⁺]

    pH = - log (1.25)

    pH = - 0.1
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