Balance the equation below, and answer the following question: What volume of chlorine gas, measured at STP; is needed to complete the reaction with 6.25g of sodium metal

The balanced chemical reaction would be expressed as follows:

2Na + Cl2 = 2NaCl

We are given the amount of sodium metal to be used reaction. This would be the starting value for the calculations. We do as follows:

6.25 g (1 mol / 22.99 g) (1 mol Cl2 / 2 mol Na) (22.4 L / 1 mol) = 3.045 L Cl2 needed

Hope this answers the question.