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9 March, 12:35

To begin the experiment, a bomb calorimeter is filled with 1.11 g CH4 and an excess of oxygen. The heat capacity of the calorimeter, including the bomb and the water, is 4.319 kJ g C⋅°. The initial temperature of the system was 24.85°C, and the final temperature was 35.65°C.

Using the formula ∆H = - M ⋅ C ⋅∆T, solve for the heat of combustion of. 1.11 g CH4.

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  1. 9 March, 14:05
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    There are several information's already given in the question. Based on those information's the answer can be easily determined.

    M = 1.11 g CH4

    C = 4.319 kJ g C⋅°

    ∆T = 35.65 - 24.85 degree centigrade

    = 10.8 degree centigrade.

    Then

    ∆H = - M ⋅ C ⋅∆T

    = - 1.11 * 4.319 * 10.8

    = - 51.776 kJ / mol

    I hope the procedure is clear enough for you to understand.
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