Calculate [H3O ] for the solutions below at 25 °C.

[OH-] = 1.83x10^-7 M

[H3O+] = M

Question

Chemistry

Guest

4 October, 06:18

Calculate [H3O ] for the solutions below at 25 °C.

[OH-] = 1.83x10^-7 M

[H3O+] = M

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Answers (1)

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Little Bear · Answer 1

For this question, we can use relations for pH and pOH. We calculate as follows:

pOH = - log [OH-]

pOH = - log [ 1.83x10^-7 M]

pOH = 6.74

pH + pOH = 14

pH = 14 - 6.74

pH = 7.26

pH = - log [H3O+]

7.26 = - log[H3O+]

[H3O+] = 5.46 x 10^-8 M

Hope this answers the question. Have a nice day.

Calculate [H3O ] for the solutions below at 25 °C.[OH-] = 1.83x10^-7 M[H3O+] = M

Calculate [H3O ] for the solutions below at 25 °C.

[OH-] = 1.83x10^-7 M

[H3O+] = M