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24 November, 01:31

Given STP conditions, how many milliliters of hydrogen gas are produced by the reaction 0.020 mol of magnesium with excess of hydrochloric acid?

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  1. 24 November, 05:12
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    The balanced equation for the reaction of magnesium and hydrochloric acid is,

    Mg + 2HCl - - - > H2 + MgCl2

    From the reaction, every 0.02 moles of magnesium will produce 0.02 moles H2. Using the ideal gas equation,

    V = nRT / P

    Substituting the known values,

    V = (0.02 mol) (0.0821 L. atm / mol K) (273 K) / 1 atm

    = 0.45 L = 450 mL

    Therefore, the hydrogen gas produced is approximately 450 mL.
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