A 10.0 gram piece of metal is placed in an insulated calorimeter containing 250.0 g of water initially at 20.0°C. If the final temperature of the mixture is 25.0°C, what is the heat change of water?

A) 5230 J

B) - 5230 J

C) 209 J

D) - 209 J

E) 5440 J

The heat change of water is calculated through the equation,

H = m (cp) dT

where H is heat, m is mass, cp is the specific heat, and dT is the change is temperature. Substituting the known values,

H = (250 g) (4.18 J/g°C) (25°C - 20°C) = 5255 J

The nearest value to this is letter A. 5230 J.