What is the concentration of 10.00mL of HBr if it takes 16.73 mL of a 0.253M LiOH solution to neutralize it?

The chemical reaction would be expressed as follows:

HBr + LiOH = LiBr + H2O

We are given the volumes and corresponding concentration to be used for the reaction. We use these values to solve for the concentration of the other reactant. We do as follows:

0.253 mol LiOH / L solution (0.01673 L) (1 mol HBr / 1 mol LiOH) = 0.00423 HBr needed

Concentration of HBr = 0.00423mol /.010 L = 0.423 M HBr