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8 December, 09:30

How many grams of solid baso4 will form when ba2so4 react with 25mL of. 50 M Ba (NO3) 2

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  1. 8 December, 12:32
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    Na2SO4 + Ba (NO3) 2 - - > 2NaNO3 + BaSO4

    0.0125 0.0125

    mole of Ba (NO3) 2 = 0.025 * 0.5 = 0.0125 (mole)

    The grams of BaSO4 = 0.0125 * (137+32+16*4) = 2.9125 (g)
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