Declare a variable named pump number as an integer type. Test if it is within the following range: Greater and equal to 1 and smaller and equal to 10, if it is, multiple its value by 13. Now test if it is an even number, if it is, deliver a message to the user, "it is a bad number!". If the pump number is not in the range described above, then deliver a message to user, "out of range value!"

Following are the program in C+ + Language.

#include / / header file

using namespace std; / / namespace

int main () / / main function

{

int pump; / / variable declaration

cout<<"Enter the number: ";

cin>>pump; / / Read the value by the user

if ((pump > = 1) && (pump < = 10)) / / checking condition

pump=pump * 13;

if (pump % 2 = = 0) / / checking condition

cout<<" it is a bad number!";

else

cout<<" out of range value!";

return (0);

}

Output:

Enter the number:4

it is a bad number!

Explanation:

Following are the Description of the following statements.

Declared a variable "pump" vaiable of int type. Read the number by the user by using cin function. Check the condition if ((pump > = 1) && (pump < = 10)) then it executed the if statements block. Inside this if there is also one another i. e nested if if (pump % 2 = = 0) if this statement then it executed the statement inside if otherwise else block will be executed