The code segmentif (speed < = 40) cout < 40 && speed < = 55) cout < 55) cout << "Too fast"; could be written equivalently asif (speed < = 40) cout << "Too slow"; else if (speed < = 55) cout << "Good speed"; elsecout << "Too fast"; A. TrueB. False

Question

Computers and Technology

Johanna Bailey

19 November, 14:07

The code segmentif (speed < = 40) cout < 40 && speed < = 55) cout < 55) cout << "Too fast"; could be written equivalently asif (speed < = 40) cout << "Too slow"; else if (speed < = 55) cout << "Good speed"; elsecout << "Too fast"; A. TrueB. False

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Answers (1)

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Ashanti · Answer 1

True is the correct answer for the above question.

Explanation:

The first code has three if statement, in which first if statement is true for the value of the speed which is less than or equal to 40 which can be false when the value of the speed can be greater than 40. The if-statement clause also has a scenario where, if and else-if is used, in which the else-if statement will check when the if statement if being false. So when the first if statement is false, then it is understood by the compiler that the value of the speed is greater than 40, which is no need to check in the else-if statement which is stated in the second code of the question. Hence the first and the second code of the question gives the same result which is asked by the question. So the answer is true.