a. Write a structure (struct card) that will represent a card in a standard deck of playing cards. You will need to represent both the suit (clubs, diamonds, hearts orspades) as well as the rank (A, K, Q, J, 10, 9, 8, 7, 6, 5, 6, 7, 2) of each card. Note that a deck of playing cards can be represented as an array declared asstruct card deck[52]. b. Write a function that will perform a perfect shuffle on a deck of cards represented using the data structures from part a. In a perfect shuffle, the deck is broken exactly in half and rearranged so that the first card is followed by the 27thcard, followed by the second card, followed by the 28thcard, and so on. c. Write a program that tests how many perfect shuffles are necessary to return the deck to its original configuration.

Question

Computers and Technology

Cassie Bass

19 April, 08:06

a. Write a structure (struct card) that will represent a card in a standard deck of playing cards. You will need to represent both the suit (clubs, diamonds, hearts orspades) as well as the rank (A, K, Q, J, 10, 9, 8, 7, 6, 5, 6, 7, 2) of each card. Note that a deck of playing cards can be represented as an array declared asstruct card deck[52]. b. Write a function that will perform a perfect shuffle on a deck of cards represented using the data structures from part a. In a perfect shuffle, the deck is broken exactly in half and rearranged so that the first card is followed by the 27thcard, followed by the second card, followed by the 28thcard, and so on. c. Write a program that tests how many perfect shuffles are necessary to return the deck to its original configuration.

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Answers (1)

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Amani Brady · Answer 1

a) sturct card{

string suit;

string rank;

}

b) function perfectShuffle (card deck[]) {

card newDeck[52];

int j=1;

for (int i=1; i<=26; i++) {

newDeck[j] = deck[i]

newDeck[j+1] = deck[i+26]

j=j+2;

}

return newDeck;

}

c) function numOfPerfectShuffle (card deck[]) {

card newDeck[52];

int count=0;

while (newDeck!=deck[] && count>0) {

newDeck = perfectSuffle (deck);

count++;

}

}