The equation of certain traveling waves is y (x. t) = 0.0450 sin (25.12x - 37.68t-0.523) where x and y are in

meters, and t in seconds. Determine the following:

(a) Amplitude. (b) wave number (C) wavelength. (d) angular frequency. (e) frequency: (1) phase angle, (g) the

wave propagation speed, (b) the expression for the medium's particles velocity as the waves pass by them, and (i)

the velocity of a particle that is at x=3.50m from the origin at t=21. os

A. 0.0450

B. 4

C. 0.25

D. 37.68

E. 6Hz

F. - 0.523

G. 1.5m/s

H. vy = ∂y/∂t = 0.045 (-37.68) cos (25.12x - 37.68t - 0.523)

I. - 1.67m/s.

Explanation:

Given the equation:

y (x, t) = 0.0450 sin (25.12x - 37.68t-0.523)

Standard wave equation:

y (x, t) = Asin (kx-ωt+ϕ)

a.) Amplitude = 0.0450

b.) Wave number = 1 / λ

λ=2π/k

From the equation k = 25.12

Wavelength (λ) = 2π/25.12 = 0.25

Wave number (1/0.25) = 4

c.) Wavelength (λ) = 2π/25.12 = 0.25

d.) Angular frequency (ω)

ωt = 37.68t

ω = 37.68

E.) Frequency (f)

ω = 2πf

f = ω/2π

f = 37.68/6.28

f = 6Hz

f.) Phase angle (ϕ) = - 0.523

g.) Wave propagation speed:

ω/k=37.68/25.12=1.5m/s

h.) vy = ∂y/∂t = 0.045 (-37.68) cos (25.12x - 37.68t - 0.523)

(i) vy (3.5m, 21s) = 0.045 (-37.68) cos (25.12*3.5-37.68*21-0.523) = - 1.67m/s.