An array of integers named parkingTickets has been declared and initialized to the number of parking tickets given out by the city police each day since the beginning of the current year. (Thus, the first element of the array contains the number of tickets given on January 1; the last element contains the number of tickets given today.) A variable named mostTickets has been declared, along with a variable k. Without using any additional variables, write some code that results in mostTickets containing the largest value found in parkingTickets.

Question

Computers and Technology

Jadiel Roy

28 December, 08:01

An array of integers named parkingTickets has been declared and initialized to the number of parking tickets given out by the city police each day since the beginning of the current year. (Thus, the first element of the array contains the number of tickets given on January 1; the last element contains the number of tickets given today.) A variable named mostTickets has been declared, along with a variable k. Without using any additional variables, write some code that results in mostTickets containing the largest value found in parkingTickets.

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Answers (1)

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Esperanza Nelson · Answer 1

Following code will store the largest value in array parkingTickets in the variable mostTickets

mostTickets = parkingTickets[0];

for (int k = 0; k
{

if (parkingTickets[i]>mostTickets)

{

mostTickets = parkingTickets[i];

}

}

Explanation:

In the above code segment, initially the number of tickets at first index is assumed as largest value of tickets in array.

Then using a for loop each value in the array parkingTickets is compared with the current mostTickets value.

If the compared value in parkingTickets array is larger than the current mostTickets value. Then that value is assigned to mostTickets.

This process is repeated for all elements in array.

Thus after looping through each element of array the largest value in array will get stored in mostTickets variable.