Analyze the following code:

public class Test {

public static void main (String[] args) {

B b = new B ();

b. m (5);

System. out. println ("i is " + b. i);

}

}

class A {

int i;

public void m (int i) {

this. i = i;

}

}

class B extends A {

public void m (String s) {

}

}

A. The program has a compile error, because m is overridden with a different signature in B.

B. The program has a compile error, because b. m (5) cannot be invoked since the method m (int) is hidden in B.

C. The program has a runtime error on b. i, because i is not accessible from b.

D. The method m is not overridden in B. B inherits the method m from A and defines an overloaded method m in B.

Question

Computers and Technology

Kathryn Wang

22 January, 03:34

Analyze the following code:

public class Test {

public static void main (String[] args) {

B b = new B ();

b. m (5);

System. out. println ("i is " + b. i);

}

}

class A {

int i;

public void m (int i) {

this. i = i;

}

}

class B extends A {

public void m (String s) {

}

}

A. The program has a compile error, because m is overridden with a different signature in B.

B. The program has a compile error, because b. m (5) cannot be invoked since the method m (int) is hidden in B.

C. The program has a runtime error on b. i, because i is not accessible from b.

D. The method m is not overridden in B. B inherits the method m from A and defines an overloaded method m in B.

+4

Answers (1)

Know the Answer?

Ezequiel Ibarra · Answer 1

Option D: The method m is not overridden in B. B inherits the method m from A and defines an overloaded method m in B.

Explanation:

Method overriding in Java is done when you want a child class to give its own implementation to a method that is already provided by the parent class. The method in the parent class will be called overridden method, and the child class will be overriding method.