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27 April, 23:48

Given a integer, convert to String, using String Builder class. No error checking needed on input integer, However do read in the input integer using Scanner API. This program requires you to use a loop.

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  1. 28 April, 03:44
    0
    The program in Java will be:

    / / Java program to demonstrate working parseInt ()

    public class GFG

    {

    public static void main (String args[])

    {

    int decimalExample = Integer. parseInt ("20");

    int signedPositiveExample = Integer. parseInt ("+20");

    int signedNegativeExample = Integer. parseInt ("-20");

    int radixExample = Integer. parseInt ("20",16);

    int stringExample = Integer. parseInt ("geeks",29);

    / / Uncomment the following code to check

    / / NumberFormatException

    / / String invalidArguments = "";

    / / int emptyString = Integer. parseInt (invalidArguments);

    / / int outOfRangeOfInteger = Integer. parseInt ("geeksforgeeks",29);

    / / int domainOfNumberSystem = Integer. parseInt ("geeks",28);

    System. out. println (decimalExample);

    System. out. println (signedPositiveExample);

    System. out. println (signedNegativeExample);

    System. out. println (radixExample);

    System. out. println (stringExample);

    }

    }
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