What is the output of the following sequence?

Scanner scan = new Scanner (System. in);

int number = 0;

try

{

number = scan. nextInt (); / / User enters 12, hits ENTER

System. out. println ("1: " + number);

number = scan. nextInt (); / / User enters 56, hits ENTER

System. out. println ("2: " + number);

number = scan. nextInt (); / / User enters 99ABC, hits ENTER

System. out. println ("3: " + number);

}

catch (Exception e)

{

String s = scan. nextLine ();

System. out. println ("4: " + number);

}

finally

{

number = scan. nextInt (); / / User enters 100, hits ENTER

System. out. println ("5: " + number);

}

The output of the given program is

12

1:12

56

2:56

99ABC

4:56

100

5:100

Explanation:

In this given code if user enters 12 then it print 1:12 after that user enters 56 it prints 2:56, when enter non integer on third statement it will catch exception and prints the value which user entered previously i. e 56 ... so if user enter non integer on third statement it skip these two statement System. out. println ("3: " + number);, String s = scan. nextLine (); so statement 4 is executed which is in catch statement and print "4:56" and finally it enters to finally block and again user will prompt to enter number ... if user enter 100 it print "5:100".