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29 March, 12:33

If one circuit receives thirty calls and each call lasts thirty seconds, how much of that circuit is being used in CCS?

A. 9

B. 27

C. 0.9

D. 90

E. 2.7

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Answers (1)
  1. 29 March, 15:43
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    Answer: A) 9

    Explanation:

    First of all, we need to compute the traffic intensity in Erl.

    If we take the busy hour, for 60 calls of 60 sec each, we would have 100% occupied the circuit, which we define as 1 Erl.

    Making a simple comparison, if we have half of calls, with half duration each, we will have the circuit busy 25% of time, i. e. 0.25 Erl.

    The CCS is a unit of telephony traffic, that measures it in units of 100 call-seconds (calls that last 100 seconds), and is equivalent to 1/36 Erl, due to we can show that 1 Erl = 36 CCS

    (If we had 36 calls of 100 sec each (100 CCS), we would have the circuit busy 100% time, i. e., with 1 Erl traffic).

    If we know then that 1 Erl = 36 CCS, we can find out how many CCSs are equivalent to 0.25 Erl, solving a simple direct proportion, as follows:

    36 CCS / 1 Erl = x CCS / 0.25 Erl ⇒ 9 CCS
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