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21 December, 12:49

A sine wave is offset 1/9 cycle with respect to time 0. What is its phase in degrees and radians? Which simple signal has a wider bandwidth, a sine wave with a frequency of 200 Hz or a sine wave with a frequency of 500 Hz?

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  1. 21 December, 16:00
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    A.) Phase in degree = 40°; phase in radian

    B.) Bandwidth is the same.

    Explanation:

    1 complete cycle = 360°

    Therefore, 1/9 of a cycle:

    Phase in degree;

    (1/9) * 360° = 40°

    Phase in radian:

    40 * (2π/360)

    80π/360

    = 0.222πrad

    0.698rad

    In simple terms, A bandwidth could be explained as the difference between the upper and lower frequencies of the signal. However, the signal described above is a simple signal with no upper or lower frequency boundary.

    hence, the bandwidth is assumed to be the same.
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