Alex needs 80 / text{ cm}80 cm80, start text, space, c, m, end text of thread for a sewing project. The thread is on a spool with a circumference of 10 / text{ cm}10 cm10, start text, space, c, m, end text. How many times must Alex unwind the spool to get the length of thread he needs

Given Information:

Alex needs 80 cm of thread for a sewing project.

Thread is on a spool of 10 cm circumference

Required Information:

How many times Alex has to unwind the spool?

Answer:

8 times

Explanation:

According to the given data the circumference which is basically the outer length of the spool is 10 cm so that means 1 unwind is equal to 10 cm of thread.

We need 80 cm of thread so we can write

10x = 80

Where x is the number of times to unwind the thread.

x = 80/10 = 8

Therefore, Alex has to unwind the spool 8 times to get the 80 cm of thread.