Ask Question
13 December, 04:50

Final int SIZE = 25; int[] array1 = new int[SIZE]; ... / / Code that will put values in array1 int value = 0; for (int a = 0; a < array1. length; a++) { value + = array1[a]; }

a. This code would cause the program to crash.

b. value contains the lowest value in array1.

c. value contains the highest value in array1.

d. value contains the sum of all the values in array1.

+3
Answers (1)
  1. 13 December, 06:06
    0
    d. value contains the sum of all the values in array1.

    Explanation:

    In programming language, He or she has initialized by 25 cells of single dimensional array where it can stores integer values, and program add all the 25 cells values and store sum in value variable.

    Program has following steps

    int SIZE=25; Where SIZE variable defined and initialize value by 25

    int[] arrary1 = new int[SIZE]; wheresingled dimensional array been defined which can hold 25 values or 25 cells, from 0 to 24 as cell numbers.

    int value = 0; means variable is defined as value and initialized by value with 0.

    for (int a = 0; a < array1. length; a++)

    A for loop Is created and executed, to execute loop "a" variable is defined as initialized with 0, loop is ended when "a" value reached till the "array1". Length reached 24. (i. e. "a", loop is started with 0 to exit the loop with condition will till length of single dimensional to array1. length which is defined by SIZE = 25.

    Loop executed by step by adds value 1 to an every time when loop is executed.

    Inside loop value1 in added with value of array1 [a], where each cell value is added to value1 variable name. value1 is sum of all cell values of array1 (single dimensional array).
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Final int SIZE = 25; int[] array1 = new int[SIZE]; ... / / Code that will put values in array1 int value = 0; for (int a = 0; a < array1. ...” in 📘 Computers and Technology if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers