Input a number [1-50] representing the size of the shape and then a character [x, b, f] which represents the shape i. e. x->cross, b->backward slash, or f->forward slash. Here are 4 examples which give the 2 inputs with the shape of the result directly below. Note: Even number outputs are different from odd.

C+ + code given below with appropriate comments

Explanation:

pattern. cpp

#include

using namespace std;

void printCross (int n)

{

int i, j, k;

if (n%2) / /odd number of lines

{

for (int i=n; i>=1; i--)

{

for (int j=n; j>=1; j--)

cout<<"/n";

}

}

else / /even number of lines

{

for (int i=1; i<=n; i++)

{

for (int j=1; j<=n; j++)

{

if (j==i || j= = (n-i+1))

{

cout<<" "<
}

else

cout<<" ";

}

cout<<"/n";

}

}

}

void printForwardSlash (int n)

{

if (n%2)

{

for (int i=n; i>=1; i--)

{

for (int j=n; j>=1; j--)

{

if (j==n-i+1)

{

cout<
}

else

cout<<" ";

}

cout<<"/n";

}

}

else

{

for (int i=1; i<=n; i++)

{

for (int j=1; j<=n; j++)

{

if (j= = (n-i+1))

{

cout<
}

else

cout<<" ";

}

cout<<"/n";

}

}

}

void printBackwardSlash (int n)

{

if (n%2) / / odd number of lines

{

for (int i=n; i>=1; i--)

{

for (int j=n; j>=1; j--)

{

if (j==i)

{

cout<
}

else

cout<<" ";

}

cout<<"/n";

}

}

else / /even number of lines

{

for (int i=1; i<=n; i++)

{

for (int j=1; j<=n; j++)

{

if (j==i)

{

cout<
}

else

cout<<" ";

}

cout<<"/n";

}

}

}

int main ()

int num;

char ch;

cout<<"Create a numberes shape that can be sized."<
cout<<"Input an integer [1,50] and a character [x, b, f]."<
cin>>num>>ch;

if (ch=='x'