Suppose a local area network requires eight characters for a password. The first character must be a letter, but the remaining seven characters can be either a letter or a digit (0 through 9). Lower - and uppercase let - ters are considered the same. How many passwords are possible for the local area network

Answer: 2037468266496

Explanation:

The question says first character must be a letter = A - Z (26 characters)

Others can either be letters or digits = digits with range 0-9 (10 digits)

From the second to the seventh character can either be digits or letter hence we have (10 + 26) = 36 chances

Considering rule of product

Number of chances/outcomes of the password = (26*36⁷)

The power of 7 was as a result of remaining seven characters can be either a letter or digits.