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1 October, 23:49

You have an interface on a router with the IP address of 192.168.192.10 / 29. What is the broadcast address the hosts will use on this LAN?

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  1. 2 October, 02:17
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    Answer: it is 192.168.192.15

    Explanation:

    A / 29 (255.255.255.248) has a block size of 8 in the fourth octet. This means the subnets are 0, 8, 16, 24, etc. 10 is in the 8 subnet. The next subnet is 16, so 15 is the broadcast address.
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